Simulating Swap Operations Without Modifying Data
Authors: Dou Meishi, ChatGPT
Introduction
In many applications, it is often required to simulate swap operations on a list of elements without actually modifying the underlying data. This can be useful in various scenarios, such as when you need to analyze the impact of different permutations on a given data structure or when you want to maintain multiple views of the data with different sorting orders.
In this blog post, we will discuss the problem of simulating swap operations without modifying the data, explore the background and applications, and provide a Python code example that demonstrates how to implement this functionality using a simple class structure. Finally, we will explain the reasons behind our implementation and conclude.
Background and Applications
Swapping elements in a list is a fundamental operation in many algorithms, such as sorting algorithms and combinatorial search algorithms. However, there are situations where we want to simulate these swaps without actually modifying the original data. Some possible applications include:
- Data visualization: When working with interactive visualizations, it is often necessary to display different views of the same data, based on user interactions. By simulating swaps without modifying the data, we can easily switch between different views without affecting the underlying data.
- Algorithm analysis: Analyzing the performance of algorithms that involve swapping elements can be done more efficiently by simulating swaps without modifying the data. This allows us to observe the impact of different permutations on the algorithm's performance without the overhead of actually modifying the data structure.
- Undo/redo functionality: In some applications, like text editors or image editing software, users may want to undo or redo certain actions. By simulating swaps without modifying the data, we can maintain a history of actions and easily revert to previous states without affecting the original data.
Problem Statement and Our Solution
Suppose we have a list of elements and we want to simulate swap operations on this list without modifying the actual data. We also want to be able to retrieve the elements in their current order, reflecting the simulated swap operations.
data = ['alpha', 'beta', 'gamma', 'eta'] vec = Vector(data) # swap 1-th and 3-th value vec.swap(1, 3) view = vec.view expect_view = ['alpha', 'eta', 'gamma', 'beta'] assert all(view[i]==expect_view[i] for i in range(len(data))) # swap 2-th and 3-th value vec.swap(2, 3) view = vec.view expect_view = ['alpha', 'eta', 'beta', 'gamma'] assert all(view[i]==expect_view[i] for i in range(len(data))) # restore data from view restored_data = [view[i] for i in vec.addr2name] assert all(data[i]==restored_data[i] for i in range(len(data)))
To address this problem, we propose the implementation of a class called
Viewable_Mixin
. This class maintains two lists, self.indices
and
self.inverse_indices
, that store the forward and inverse mappings
between the view and the data, respectively. The swap
method is used
to simulate swap operations on the view, while the view
property
returns the current state of the view.
Below is the complete Python code that demonstrates how to simulate swap
operations without modifying the data using a simple class structure
called Viewable_Mixin
:
class Viewable_Mixin(object): '''Allow swap index without actually modifying the data.''' def __init__(self, *args, **kws): '''Assume data is a list''' super().__init__(*args, **kws) self.indices = list(range(len(self))) self.inverse_indices = list(range(len(self))) def swap(self, i, j): # swap i-th and j-th value without actually modifying data self.indices[i], self.indices[j] = self.indices[j], self.indices[i] # update inverse_indices self.inverse_indices[self.indices[i]] = i self.inverse_indices[self.indices[j]] = j def __getitem__(self, i): # return the view return super().__getitem__(self.indices[i]) @property def view(self): return [self[i] for i in range(len(self))] @property def addr2name(self): return self.inverse_indices class Vector(Viewable_Mixin, list): def __init__(self, *args, **kws): super().__init__(*args, **kws) data = ['alpha', 'beta', 'gamma', 'eta'] vec = Vector(data) # swap 1-th and 3-th value vec.swap(1, 3) view = vec.view expect_view = ['alpha', 'eta', 'gamma', 'beta'] assert all(view[i] == expect_view[i] for i in range(len(data))) # swap 2-th and 3-th value vec.swap(2, 3) view = vec.view expect_view = ['alpha', 'eta', 'beta', 'gamma'] assert all(view[i] == expect_view[i] for i in range(len(data))) # restore data from view restored_data = [view[i] for i in vec.addr2name] assert all(data[i]==restored_data[i] for i in range(len(data)))
Explanation of the Implementation
Our solution is based on creating a class called Viewable_Mixin
that
maintains two lists: self.indices
(name2addr) and
self.inverse_indices
(addr2name). These lists represent the forward
and inverse mappings between the view and the data, respectively.
self.indices
is initialized with a range of indices from 0 to the
length of the data minus 1. This list represents the mapping from the
view's indices to the data's indices. When we swap elements in the view,
we only swap their indices in this list, without actually modifying the
data.
self.inverse_indices
is also initialized with a range of indices from
0 to the length of the data minus 1. This list represents the inverse
mapping from the data's indices to the view's indices. It is updated
whenever elements are swapped in the view, ensuring that the inverse
mapping remains consistent with the forward mapping.
The swap
method takes two indices, i and j, and swaps the i-th and
j-th elements in the view without modifying the actual data. This is
achieved by swapping the corresponding indices in self.indices
and
updating self.inverse_indices
.
The __getitem__
method is used to return the element in the view at a
given index. It does this by returning the data element at the index
specified by self.indices[i]
.
Finally, the view
and addr2name
properties return the current state
of the view and the inverse mapping (self.inverse_indices
),
respectively.
Conclusion
In this blog post, we have explored the problem of simulating swap
operations without modifying the underlying data. We provided a Python
code example that demonstrates how to achieve this using a simple class
structure called Viewable_Mixin
. The solution maintains two lists,
self.indices
and self.inverse_indices
, to store the forward and
inverse mappings between the view and the data. By swapping elements in
the view and updating the mappings accordingly, we can efficiently
simulate swaps without modifying the actual data.
This approach can be useful in various applications, such as data visualization, algorithm analysis, and undo/redo functionality, where it is necessary to maintain multiple views of the same data or analyze the impact of different permutations without affecting the underlying data.
Mathematical Justifications
It is possible to interprete indices
and inverse_indices
as two permutation matrix. To see this, one may write data
and view
as two column vectors and note the following equations.
Hence, indices
represents the permutation matrix in the first equation, denoted by \(A\) below, and inversed_indices
represents the matrix in the second equation, denoted by \(B\).
Clearly, \(AB=I\). Moreover, because \(A\) and \(B\) are othrogonal matrix, \(A=B^\intercal\) holds too.
In this point of view, indices[i]
stores the unique column index j
such that \(A_{ij}=1\),
\[ \sum_{j}A_{ij} \mathtt{data[j]} = \mathtt{view[i]} = \mathtt{data[indices[i]]}.\]
Similarly, inversed_indices[i]
stores the unique column index j
such that \(B_{ij}=1\),
\[ \sum_{j}B_{ij} \mathtt{view[j]} = \mathtt{data[i]} = \mathtt{view[inversed\_indices[i]]}.\]
For arbitary vector \(v\), we have (introduce the notation that \(\mathbb{I}[\mathtt{cond}]=1\) if and only if \(\mathtt{cond}\) is true)
$$ \begin{aligned} (BAv)_i &= \sum_{k} \sum_{j} A_{ik} B_{kj} v_j \\ &= \sum_{k} \mathbb{I}(k=\mathtt{indices}[i]) \sum_{j} \mathbb{I}(j=\mathtt{inversed\_indices}[k]) \cdot v_j \\ &= \sum_{k} \mathbb{I}(k=\mathtt{indices}[i]) \cdot v[\mathtt{inversed\_indices}[k]] \\ &= v[\mathtt{inversed\_indices}[\mathtt{indices}[i]]]. \end{aligned} $$Thus, we have \[i = \mathtt{inversed\_indices}[\mathtt{indices}[i]].\] This is the reflection of the matrix equation \(BA=I\).
Now look back to the equation transforming data
to view
where \(\mathbb{I}(j = \mathtt{indices}[0])\) denotes a row vector with
subscript \(j\). To swap the view
vector without modifying the data
vector, we can swap rows of \(A\) to satisfying the transforming
equation. For example, if we want to swap the $i1$-th and $i2$-th
entry of view
, we can create another indices to represent the new
permutation matrix:
or in a more intuitive expression
$$ \begin{cases} \mathtt{inversed\_indices}'[\mathtt{indices}'[i_1]] &= \mathtt{inversed\_indices}[\mathtt{indices}'[i_2]] = i_1,\\ \mathtt{inversed\_indices}'[\mathtt{indices}'[i_2]] &= \mathtt{inversed\_indices}[\mathtt{indices}'[i_1]] = i_2,\\ \mathtt{inversed\_indices}'[\mathtt{indices}'[i]] &= \mathtt{inversed\_indices}[\mathtt{indices}'[i]] = i,\quad \forall i\not\in\{i_1, i_2\}, \end{cases} $$It's easy to verify that \(\mathtt{inversed\_indices}'\) is indeed the inverse mapping of \(\mathtt{indices}'\).